1 Answer

Aung Thet · Answer 1 · 2017-06-22T16:10:54+0000

Simple....

you have:

4x+3y≤-12

To solve for X or Y just isolate the variable....

4x+3y≤-12
-3y -3y

4x≤-3y-12

Now divide by 4....

$(4x)/(4) \leq (-3y-12)/(4)$

$x \leq -(3y)/(4) -3$

Now for y:

4x+3y≤-12

4x+3y≤-12
-4x -4x

3y≤-4x-12

Divide by 3...

$(3y)/(3) \leq (-4x-12)/(3)$

$y \leq -(4x)/(3) -4$

This is the way to solve it.

Thus, your answer.

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