Question

Given that sinø =4/5 and ø lies in quadrant II find the following value secø

Answer 1

Step-by-step explanation:

Mathematically, the sec of an angle is the reciprocal of its cos

We know that cosine is negative in quadrant II and that means , sec will also be negative here

Mathematically, the sec of an angle is the ratio of the hypotenuse to the adjacent(we get it by dividing hypotenuse by the adjacent)

Now, to get the adjacent, we know that 3,4, and 5 are a Pythagorean triple.

That means the last side of the right triangle formed is 3

Now, we have the sec as:

`sec\text{ }\phi\text{ =- }(5)/(3)`