Answer:
Step-by-step explanation:
Total amount of money invested = $20000
Interest on the $20000 investment = (11/100) x 20000
Interest on the $20000 investment = $2200
Let the amount invested with 8% interest be m
Interest on the 8% investment = (8/100) x m
Interest on the 8% investment = 0.08m
Let the amount invested with 12% interest be n
Interest on the 12% investment = (12/100) x n
Interest on the 12% investment = 0.12n
The total amount invested is $20000
m + n = 20000.............(1)
Total interest is $2200
0.08m + 0.12n = 2200........(2)
Make m the subject of the formula in equation (1)
m = 20000 - n.............(3)
Substitute equation (3) into equation (2)
0.08(20000 - n) + 0.12n = 2200
1600 - 0.08n + 0.12n = 2200
0.04n = 2200 - 1600
0.04n = 600
n = 600/0.04
n = 15000
Substitute n = 15000 into equation (3)
m = 20000 - 15000
m = 5000
The amount Paul invested at 8% interest i