Question

The position of a particle moving along the x axis is given by x(t) = (5.66 m) - (2.41 m/s)t. displacment of the particle between time t=3, t=6

Answer 1

Given

Position of a particle

`x(t)=5.66-2.41t`

Procedure

First, let's calculate the position at t = 3

`\begin{gathered} x(3)=5.66-2.41\cdot3 \\ x(3)=-1.57\text{ m} \end{gathered}`

Now let's calculate the position t = 6

`\begin{gathered} x(6)=5.66-2.41\cdot6 \\ x(6)=-8.8\text{ m} \end{gathered}`

Let's calculate the displacement.

`\begin{gathered} \Delta x=x(6)-x(3)=-8.8-(-1.57) \\ \Delta x=-7.23 \end{gathered}`

The total displacement is -7.23 m