Question

fourth,sixth and thirteenth term in this sequence A(n)= 6+(n+1)(-2) help me to find and describe the explicite formula

Answer 1

Hello,

A(n)=6+(n+1)^(-2)=6+1/(n+1)²


`A_(4) =6+ (1)/((4+1)^2) =6+ (1)/(25)= (151)/(25) \\ A_(6) =6+ (1)/((6+1)^2) =6+ (1)/(49)= (295)/(49) \\ A_(13) =6+ (1)/((13+1)^2) =6+ (1)/(196)= (1177)/(196) \\`