321,860 views
9 votes
9 votes
I need help solving this radical operation
√(90) - √(40)

User Praveen Dp
by
3.6k points

1 Answer

11 votes
11 votes

\begin{gathered} √(90)-√(40)=√(9*10)-√(4*10) \\ \text{ =}√(9)*√(10)-√(4)*√(10) \\ \text{ =3}√(10)-2√(10) \end{gathered}

taking √10 common,


√(10)(3-2)=√(10)

User Keasha
by
2.7k points
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