f(x) = (x + 9)(x - 4)(6x + 1)
To find the zeroes of f(x0 put f(x) = 0
0 = (x + 9)(x - 4)(6x + 1)
Now equate each bracket by 0
x + 9 = 0
Subtract 9 from both sides
x + 9 - 9 = 0 - 9
x = -9
x - 4 = 0
Add 4 to both sides
x + 4 - 4 = 0 + 4
x = 4
6x + 1 = 0
Subtract 1 from both sides
6x + 1 - 1 = 0 - 1
6x = -1
Divide both sides by 6
6x/6 = -1/6
x = - 1/6
The zeroes of f(x) are -9, 4, - 1/6
The answer is A