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Identify the zeros of f(x) = (x + 9)(x − 4)(6x + 1). −9, −1 over 6,49, 1 over 6, 4 −9, −1 over 6,−4 −9, 1 over 6, −4

User Pronskiy
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1 Answer

16 votes
16 votes

f(x) = (x + 9)(x - 4)(6x + 1)

To find the zeroes of f(x0 put f(x) = 0

0 = (x + 9)(x - 4)(6x + 1)

Now equate each bracket by 0

x + 9 = 0

Subtract 9 from both sides

x + 9 - 9 = 0 - 9

x = -9

x - 4 = 0

Add 4 to both sides

x + 4 - 4 = 0 + 4

x = 4

6x + 1 = 0

Subtract 1 from both sides

6x + 1 - 1 = 0 - 1

6x = -1

Divide both sides by 6

6x/6 = -1/6

x = - 1/6

The zeroes of f(x) are -9, 4, - 1/6

The answer is A

User James LT
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