Question

The boron atom of BBr3 has

one atomic orbital.
two atomic orbitals.
three hybrid orbitals.
four hybrid orbitals.

Answer 1

Boron has three hybrid orbitals that is 2s
hopefully it helps.

Answer 2

Answer: The boron atom of
`BBr_3` has three hybrid orbitals

Explanation: Hybridization of the molecule can be calculated by:

`Hyb=(1)/(2)(V+H-C+A)` .....(1)

where,

V = number of valence electrons in the central metal atom

H = number of monovalent atoms

C = cationic charge

A = anionic charge

Here, electronic configuration of B =
`1s^22s^22p^1`

Number of valence electrons = 3

Number of monovalent atoms = 3

Cationic charge = 0

Anionic charge = 0

Putting these values in equation 1, we get

`Hyb=(1)/(2)(3+3-0+0)=3`

As the Hybridization is 3, which means that boron has 3 hybrid orbitals.