Question

Find the lengths of the sides of a triangle with vertices (0,0), (5,0),(5,12)

choices
A.5,12,12
B.5,5,12
C.5,12,5
D.5,12,13

Answer 1

A ( 0, 0 ) , B ( 5, 12 ) , C ( 5, 0 );
AB = √((5-0)² + (12- 0)²) = √(25 + 144 ) = √169 = 13
BC = √((5-5)²+(12 - 0)²) =√144 = 12
AC = √((5-0)² + (0-0)²) = √25 = 5
Answer:
D ) 5, 12 , 13

Answer 2

(0,0),(5,0) we get 5

(5,0),(5,12) we get 12

3rd side = 13
option D is right
hope this helps