Question

Jessica has been tracking the population of a town. The population was 8,230 last year and has been increasing by 1.25 times each year. How can Jessica develop a function to model this?

f(x) = (8230 • 1.25)x where 1.25 is the rate of growth

f(x) = 8230(1.25)x where 1.25 is the rate of growth

f(x) = 1.25(8230)x where 8230 is the rate of growth

f(x) = 8230(x)1.25 where 8230 is the rate of growth

Answer 1

Answer:
`f(x) = 8230(1.25)^x`, where 1.25 is the rate of growth .

Explanation:

Given: Jessica has been tracking the population of a town.

The population was 8,230 last year and has been increasing by 1.25 times each year.

We know that the exponential growth function is given by :_

`f(x)=Ab^x`, where A is the initial amount and b is the multiplicative rate of change in x years.

If we consider the population last year as initial population, then we get the following function:-

`f(x) = 8230(1.25)^x`, where 1.25 is the rate of growth .

Answer 2

Population at start : 8,230.
The rate of growth: r = 1.25
x - number of the years;
Answer:
B ) f ( x ) = 8,230 * ( 1.25 ) ^x where 1.25 is the rate of growth.