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If you place 35 points on a piece of paper so that no three points are in a line, how many line segments are necessary to connect each point to all the others?

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Answer:

595 line segments are necessary to connect each point to all the others.

Explanation:

Consider the provided information.

The formula for the number of line segments between "n" non-collinear points is:


(n* ( n -1 ))/(2) Segments

Here it is given that there are 35 points.

Substitute n = 35 in above formula.


(35* (35 -1 ))/(2)


(35* 34)/(2)


35* 17


595 Segments

Hence, 595 line segments are necessary to connect each point to all the others.

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