Question

What are the solutions of
`{x}^(2) + 6x - 6 = 10.`

Answer 1

The first step is to equal the quadratic expression to zero, it means that we have to eliminate the 10 that is in one of the sides of the equation:

`\begin{gathered} x^2+6x-6=10 \\ x^2+6x-6-10=10-10 \\ x^2+6x-16=0 \end{gathered}`

Then, we have to factor the expression:

`(x+8)(x-2)=0`

Now, find the solutions of the equations by making each factor equal to zero and solving for x:

`\begin{gathered} x+8=0 \\ x=-8 \\ x-2=0 \\ x=2 \end{gathered}`

The solutions of the equation are x=-8 or x=2.

It means that the correct answer is the last choice.