Question

Help me, please, i"m desperate

Answer 1

`D:5x-2>0 \wedge x>0 \wedge x-1>0\\ D:5x>2 \wedge x>0 \wedge x>1\\ D: x>(2)/(5) \wedge x>1\\ D:x>1\\ \log_2(5x-2)-\log_2x-\log_2(x-1)=2\\ \log_2(5x-2)/(x(x-1))=\log_24\\ (5x-2)/(x(x-1))=4\\ 4x(x-1)=5x-2\\ 4x^2-4x=5x-2\\ 4x^2-9x+2=0\\ 4x^2-x-8x+2=0\\ x(4x-1)-2(4x-1)=0\\ (x-2)(4x-1)=0\\ x=2 \vee x=(1)/(4)\\ (1)/(4)\\ot \in D \Rightarrow \boxed{x=2}`