Question

A candy company claims that 18% of its plain candies are orange, and a sample of 200 such candies is randomly selected.a. Find the mean and standard deviation for the number of orange candies in such groups of 200.

Answer 1

It is given that the probability that the candles are orange is 18% so the value of p=0.18.

The sample of 200 is taken so n=200.

The mean is given by:

`\begin{gathered} \mu=np \\ \mu=200*0.18 \\ \mu=36 \end{gathered}`

The standard deviation is calculated as:

`\begin{gathered} \sigma=\sqrt[]{np(1-p)} \\ \sigma=\sqrt[]{200*0.18(1-0.18)} \\ \sigma\approx5.4332 \end{gathered}`

Hence the mean of number of orange candles is 36 and standard deviation is 5.4332.