Question

PLEASE HELP!!!!!!

solve for the equations :
- 3y + 7 + 3(y-1) = 2(2y+6)

- (x-5)(x+4) = (x+7)(x-6)

- 2(x+1)2(x-2)2 = x(x-3)

Answer 1

1.y=-2
2. x1,2=+-5.56
3.x1=16.13 , x2=-0.85

Answer 2

-3y + 7 + 3(y - 1) = 2(2y + 6)
-3y + 7 + 3y - 3 = 4y + 12
4y = 4 - 12 = -8
y = -8/4 = -2.

-(x - 5)(x + 4) = (x + 7)(x - 6)
-(x^2 + 4x - 5x - 20) = x^2 - 6x + 7x - 42
-x^2 + x + 20 = x^2 + x - 42
2x^2 = 62
x^2 = 62/2 = 31

`x=\pm√(31)`