Question

Problems solved by quadratic equations:x2 + 7x +12 = 0

Answer 1

this would be easer to factor
(x+3)(x+4)=0
x+3=0
x+4=0

x=-3 and -4

bu tif want quadratic

in form
ax^2+bx+c=0

x=
`(-b+/- √(b^2-4ac) )/(2a)`

ax^2+bx+c=0
1x^2+7x+12=0
a=1
b=7
c=12
x=
`(-b+/- √(b^2-4ac) )/(2a)`
x=
`(-7+/- √(7^2-4(1)(12)) )/(2(1))`
x=
`(-7+/- √(49-48) )/(2)`
x=
`(-7+/- √(1) )/(2)`
x=
`(-7+/- 1)/(2)`
x=-6/2 or -8/2
x=-3 or -4