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What is the molarity of sodium chloride solution prepared by dissolving 10.0 grams in 100.0ml of solution?

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C_(i)=(n_(i))/(V)\\\\ n_(i)=(m)/(M_(NaCl))\\\\ C_(i)=((m)/(M_(NaCl)))/(V)=(m)/(M_(NaCl)V)\\\\ m=10g\\ M_(NaCl)=58.5(g)/(mol)\\ V=100ml=0.1L\\\\ C_(i)=(10g)/(58.8(g)/(mol)*0.1L)=1.71(mol)/(L)
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