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Modulus: If z1=-2+3i and z2=1+2i calculate, |z1|, |z2|, and |z1+2z2|

User Ianmjones
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|z_1|=√((-2)^2+3^2)=√(4+9)=√(13)\\ |z_2|=√(1^2+2^2)=√(1+4)=√(5)\\\\ z_1+2z_2=-2+3i+2(1+2i)=-2+3i+2+4i=7i\\ |z_1+2z_2|=√(0^2+7^2)=7
User Manoj Savalia
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