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ALGEBRA AND GEOMETRY REVIEWFactoring a quadratic with a negative leadFactor completely.- 4y2 - 32y +80Х

User Tmbo
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1 Answer

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Factoring polynomials is a matter of making educated guesses. In some cases the educated guesses come easily in others it is not so easy a task.

For our polynomial, let us first factor out 4. Doing this gets is


-4(y^2+8y-20)

And now we take a guess at the factors of the polynomial in the parenthesis.

Now remember that,


(y+a)(y+b)=y^2+(a+b)y+ab

Comparing this with our polynomial suggests


a+b=8
ab=-20

meaning the sum of a and b is 8 and the product is -20. What two numbers could satisfy this condition?

Let us take a guess at a = 10 b = -2. This will give


-4\textcolor{#FF7968}{\lbrack}(y+10)(y-2)\textcolor{#FF7968}{\rbrack}

Let us see if this guess works by expanding what is in the square brackets.


\textcolor{#FF7968}{(y+10)(y-2)}=y(y-2)+10(y-2)=y^2-2y+10y-20
=\textcolor{#FF7968}{y^2+8y-20}

which is exactly the same!

Hence, the factorization of - 4y2 - 32y + 80 is


-4(y+10)(y-2)\text{.}

User Tuesday Four AM
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