Question

How many grams of N2 are needed to make 5.8g of N2O

Answer 1

First, we need the reaction:

2N2 (g) + O2 (g) → 2N2O (g)

Molecular weights:

N2 = 28.01 g/mol

N2O = 44.01 g/mol

For this exercise we use Stoichiometry.

Always balance your reaction.

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We know that:

2 x 28.01 g N2 -------------------- 2 x 44.01 g N2O

X -------------------- 5.80 g N2O

`X\text{ = }\frac{5.8\text{ g x 2 x 28.01 g}}{2\text{ x 44.01 g}}=\text{ 3.69 g N2}`

Answer: 3.69 grams of N2 are needed.