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What is the sum of the first 30 terms in a(n)=4n+1

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Hello,


\sum _(i=1) ^(30)(a_i)=\sum _(i=1) ^(30)(4*i+1)\\ =4*\sum _(i=1) ^(30)(i) +\sum _(i=1) ^(30)(1)\\ =4* (31*30)/(2) + 30 =1860+30=1890
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