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How many moles of MgSiO3 are in 233 g of the compound?
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Jan 19, 2017
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How many moles of MgSiO3 are in 233 g of the compound?
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Gdurelle
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m = 233g
M = 24 + 28+ 16 * 3 = 100g/mol
n = m/M = 233g / 100 g/mol = 2,33mol
Kaspars Ozols
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Jan 23, 2017
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Kaspars Ozols
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