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How many moles of MgSiO3 are in 233 g of the compound?

How many moles of MgSiO3 are in 233 g of the compound?
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How many moles of MgSiO3 are in 233 g of the compound?

User Gdurelle
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m = 233g
M = 24 + 28+ 16 * 3 = 100g/mol

n = m/M = 233g / 100 g/mol = 2,33mol
User Kaspars Ozols
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