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For a standard normal distribution, find P(-0.64

User RNJ
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1 Answer

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23 votes

ANSWER:

The probability is 68.63%

Explanation:

The first thing is to look in the normal distribution table for the corresponding z values:

Replacing we have:

[tex]\begin{gathered} P\mleft(-0.640.64) \\ P(z<1.62)=0.9474 \\ P(z>0.64)=0.2611 \\ P(-0.64
For a standard normal distribution, find P(-0.64-example-1
User Kassan
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