Question

What is the equation of the line with a y-intercept of 4 and a point (8,8)? ​

Answer 1

The equation of the line with a y-intercept of 4 and a point (8,8) is
`y=(1)/(2) *x+4`

Explanation:

A linear equation can be expressed in the form

y = m * x + b

where x and y are coordinates of a point, m is the slope and b is the y-intercept. Since this equation describes a line in terms of its slope and its y-intercept, this equation is said to be in its slope-intercept form.

Graphically this equation represents a line.

In this case, you know:

• The point (x,y)=(8,8)
• Y-intercept= 4

Replacing:

8=m*8 +4

Solving:

8-4=m*8

4=m*8

4÷8= m

`m=(1)/(2)`

Then, the equation of the line with a y-intercept of 4 and a point (8,8) is
`y=(1)/(2) *x+4`