Question

What do you call a female bug that floats

Answer 1

You call a female bug that floats a buoyant girl ant.

Answer 2

Part 1) T

Part 2) L

Part 3) A

Part 4) Y

Part 5) T

Part 6) I

Part 7) U

Part 8) A

Part 9) N

Part 10) G

Part 11) B

Part 12) A

Part 13) N

Part 14) R

Part 15) O

The final answer is

A buoyant girl ant

Explanation:

see the attached figure to better understand the problem

Part 1) we have

`2x\geq-6` ----> inequality A

Divide by
`2` both sides

`x\geq-3` ------> the solution inequality A is the interval [-3,∞)

`x-1 < 0` -----> inequality B

Adds
`1` both sides

`x < 1` ------> the solution inequality B is the interval (-∞,1)

The solution of the system of inequalities is the interval -----> [-3,1)

The solution is the letter T

Part 2) we have

`-7x<14` ----> inequality A

Divide by
`7` both sides

`-x<2` -----> multiply by
`-1`

`x>-2`------> the solution inequality A is the interval (-2,∞)

`3x+2\leq 8` -----> inequality B

Adds
`-2` both sides

`3x\leq 6`

Divide by
`3` both sides

`x\leq 2` ------> the solution inequality B is the interval (-∞,2]

The solution of the system of inequalities is the interval -----> (-2,2]

The solution is the letter L

Part 3) we have

`--8<x-5` ----> inequality A

rewrite

`x-5>-8`

Adds
`5` both sides

`x>-3` ------> the solution inequality A is the interval (-3,∞)

`x-5<-3` -----> inequality B

Adds
`5` both sides

`x<2` ------> the solution inequality B is the interval (-∞,2)

The solution of the system of inequalities is the interval -----> (-3,2)

The solution is the letter A

Part 4) we have

`1\leq4x+1` ----> inequality A

rewrite

`4x+1\geq 1`

Adds
`-1` both sides

`4x\geq 0`

Divide by
`4` both sides

`x\geq 0` ------> the solution inequality A is the interval [0,∞)

`4x+1\leq 17` -----> inequality B

Adds
`-1` both sides

`4x\leq 16`

Divide by
`4` both sides

`x\leq 4` ------> the solution inequality B is the interval (-∞,4]

The solution of the system of inequalities is the interval -----> [0,4]

The solution is the letter Y

Part 5) we have

`1\leq -2x+7` ----> inequality A

rewrite

`-2x+7\geq 1`

Adds
`-7` both sides

`-2x\geq -6`

Divide by
`2` both sides

`-x\geq -3` ------> multiply by
`-1`

`x\leq 3` ------> the solution inequality A is the interval (-∞,3]

`-2x+7<9` -----> inequality B

Adds
`-7` both sides

`-2x<2`

Divide by
`2` both sides

`-x<1` ------> multiply by
`-1`

`x>-1` ------> the solution inequality B is the interval (-1,∞)

The solution of the system of inequalities is the interval ----->(-1,3]

The solution is the letter T

Part 6) we have

`3x-1<-7` ----> inequality A

Adds
`1` both sides

`3x<-6`

Divide by
`3` both sides

`x<-2` ------> the solution inequality A is the interval (-∞,-2)

`4x+9\geq 13` -----> inequality B

Adds
`-9` both sides

`4x \geq 4`

Divide by
`1` both sides

`x \geq 1` ------> the solution inequality B is the interval [1,∞)

The solution of the system of inequalities is the interval ----->(-∞,-2) U [1,∞)

The solution is the letter I

Part 7) we have

`-5x>15` ----> inequality A

Divide by
`5` both sides

`-x>3`

multiply by
`-1`

`x<-3` ------> the solution inequality A is the interval (-∞,-3)

`x-5>-6` -----> inequality B

Adds
`5` both sides

`x>-1` ------> the solution inequality B is the interval (-1,∞)

The solution of the system of inequalities is the interval ----->(-∞,-3) U (-1,∞)

The solution is the letter U

Part 8) we have

`4-15x\geq 4` ----> inequality A

Adds
`-4` both sides

`-15x\geq 0`

Divide by
`15` both sides

`-x\geq 0` -----> multiply by
`-1`

`x\leq 0` ------> the solution inequality A is the interval (-∞,0]

`12x>36` -----> inequality B

Divide by
`12` both sides

`x>3` ------> the solution inequality B is the interval (3,∞)

The solution of the system of inequalities is the interval ----->(-∞,0] U (3,∞)

The solution is the letter A

see the complete answer in the attached file