Does the relation y = √12x + 3 define y as a function of x? Give the domain.

Avriis asked Nov 9, 2023

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Avriis asked Nov 9, 2023

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20 votes

The function:

$y=\sqrt[\placeholder{⬚}]{12x+3}$

The domain of this function always is going to be for the values when:

$\begin{gathered} 12x+3>=0 \\ Solving\text{ for x} \\ 12x\ge-3 \\ x\operatorname{\ge}-(3)/(12) \end{gathered}$

So, the domain is for all values of x equal or greater than -3/12

Domain= R>=-3/12

Roman Slyepko answered Nov 13, 2023

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