Question

Find the area of a sector with a central angle of 32° and a radius of 8.5 millimeters. Round to the nearest tenth.

Answer 1

The area of sector is 20.2 millimeter².

Explanation:

The formula for area of sector is

`A=\pi r^2* ((\theta)/(360))`

The central angle of the sector is 32° and the radius of the circle is 8.5 millimeters.

`A=\pi* (8.5)^2* ((32)/(360))`

`A=\pi* (6.42222222222)`

`A=20.1760061531`

`A\approx 20.2`

Therefore the area of sector is 20.2 millimeter².

Answer 2

You use the formula:
A = angles/360*pi*r^2
A = 32/360pi*8.5^2 = 0.279* 72.25= 20.15775 rounded to 20.2
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