Question

A charge of 8 nC is placed uniformly on a square sheet of nonconducting material of side 22 cm in the yz plane.(d) What is the magnitude of the electric field to the right (x > 0) of the right face of the slab?

Answer 1

This is a problem dealing with the surface charge density. Based on the given problem above, your charge is 8nc on a square plate of 22 cm x22 cm given that E= (surface charge density)/2ε₀ so answer would be 8nc/22/22/2ε₀. Therefore, the magnitude of the electric field to the right (x>0) of the right face of the slab would be 8nc/22/22/2ε₀.

Answer 2

E = 9338.4 N/C

Step-by-step explanation:

As we know that electric field due to a charged sheet is given by the formula

`E = (\sigma)/(2\epsilon_0)`

here we know that

`\sigma` = charge density

`\sigma = (Q)/(A)`

`\sigma = (Q)/(L^2)`

`\sigma = (8* 10^(-9))/(0.22^2)`

`\sigma = 1.65 * 10^(-7)C/m^2`

now we have

`E = (1.65 * 10^(-7))/(2(8.85 * 10^(-12))`

`E = 9338.4 N/C`