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2.55, 3.10, 2.65, 2.45, 3.25a. The mean is I (Round to two decimal places as needed.)b. Enter the deviation for each data item in the table below.2.553.102.652.453.25(Round each answer to two decimal places as needed.)c. The sum of the deviations is(Round to two decimal places as needed.)

2.55, 3.10, 2.65, 2.45, 3.25a. The mean is I (Round to two decimal places as needed-example-1
User Calise
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1 Answer

13 votes
13 votes

Part a

Find out the mean

mean=(2.55+3.10+2.65+2.45+3.25)/5

mean=14/5

mean=2.80

Part b

the deviation for each data

(2.55-2.80)=-0.25

(3.10-2.80)=0.30

(2.65-2.80)=-0.15

(2.45-2.80)=-0.35

(3.25-2.80)=0.45

Part c

The sum of the deviations is

(-0.25+0.30-0.15-0.35+0.45)=0

User Cvetelina
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