Question

2.55, 3.10, 2.65, 2.45, 3.25a. The mean is I (Round to two decimal places as needed.)b. Enter the deviation for each data item in the table below.2.553.102.652.453.25(Round each answer to two decimal places as needed.)c. The sum of the deviations is(Round to two decimal places as needed.)

Answer 1

Part a

Find out the mean

mean=(2.55+3.10+2.65+2.45+3.25)/5

mean=14/5

mean=2.80

Part b

the deviation for each data

(2.55-2.80)=-0.25

(3.10-2.80)=0.30

(2.65-2.80)=-0.15

(2.45-2.80)=-0.35

(3.25-2.80)=0.45

Part c

The sum of the deviations is

(-0.25+0.30-0.15-0.35+0.45)=0