Question

A closed cylindrical tank of radius 3.5 m and height 2m is made from

a sheet of metal. How much sheet of metal is required ?​

Answer 1

Step-by-step explanation:

Total surface area of cylinder:

`2\pi * r(h + r) \\ 2 * \pi * 3.5(3.5 + 2) \\ 2\pi * 19.25 = 120.951317 \\ 120.95 \: {cm}^(2)`

sheet of metal required = 120.95 cm^2

Answer 2

Step-by-step explanation:

Answer:

Given :-

A closed cylindrical tank of radius 3.5 m and height 2 m is made from a sheet of metal.

To Find :-

How much sheet of metal is required.

Formula Used :-

`{\red{\boxed{\large{\bold{T.S.A\: of\: cylinder\: =\: 2{\pi}r(r + h)}}}}}`

where,

r = Radius

h = Height

Solution :-

Given :

Radius = 3.5 m

Height = 2 m

According to the question by using the formula we get,

⇒
`\sf T.S.A =\: 2 * (22)/(7) * 3.5(3.5 + 2)`

⇒
`\sf T.S.A =\: 2 * (22)/(7) * 3.5(5.5)`

⇒
`\sf T.S.A =\: 2 * (22)/(7) * 3.5 * 5.5T.S.A=2×722×3.5×5.5</p><p></p><p></p><p>⇒ \sf T.S.A =\: 2 * (22)/(7) * 19.25`

⇒
`\sf T.S.A =\: 2 * 60.5`

➠
`\sf\bold{\purple{T.S.A =\: 121\: {m}^(2)}}`

∴ 121 m² of sheet of metal is required.