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A=11+4b−4c? A.c=a−4b−11 ------------- −4 B.c=a+b−11 ------------ −4 C.c=a+4b+11 -------------- −4 D.c=a−b+11 ------------ −4

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Juampy NR · Answer 1 · 2017-01-26T20:11:02+0000

Ok so first we subtract 11 on each side so we get a-11=4b-4c then we do-4b on each side to gets a-11-4b=-4c finally divide -4 to each side to get a-11-4b/-4=c

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