239,591 views
17 votes
17 votes
A rhombus with diagonals 15 in and 20 in

User Asael
by
2.6k points

1 Answer

10 votes
10 votes

Given data:

Diagonals if rhombus 15 inches and 20 inches.

Area of rhombus is,


A=(1)/(2)* d1* d2
\begin{gathered} A=(1)/(2)*15*20 \\ A=150\text{inches sq} \end{gathered}

Now, to find the perimeter first find the side of the the rhombus

Diagonal is considered as diameter so radius will be the half of the diameter,

d1 = r1 = 7.5

d2 = r2 = 10

Finding the side by the pythagorean theorem,


\begin{gathered} h^2=(7.5)^2+(10)^2 \\ h^2=56.25+100 \\ h=12.5 \end{gathered}

Therefore, the perimeter of the rhombus is


\begin{gathered} P=4h \\ P=4*12.5 \\ P=50\text{inches} \end{gathered}

Thus, the area is 150 in sq. and perimeter is 50 in.

User Reda Lemeden
by
2.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.