Question

ResetcompThe entrance ticket for a carnival costs $89.97, which includes a royal mealthat costs $10.85, 1 play station game, and 3 water rides (Each water ridecosts the same price). The cost of a water ride is twice as that of a playstation game. Find the cost of a water ride. Estimate to the nearest tenths.R.

Answer 1

We know that

• The entrance costs $89.97.

,

• The royal meal costs $10.85.

,

• A water ride costs twice the play station game.

Let's call x each water ride and y each play station game, we can express this relationship as follows

`x=2y`

But, there are 3 water rides, so we multiply each side of the equation by 3.

`\begin{gathered} 3x=3\cdot2y \\ 3x=6y \end{gathered}`

Now, the addition of all those activities is equal to $89.97.

`10.85+y+6y=89.97`

Let's solve for y

`\begin{gathered} 10.85+7y=89.97 \\ 7y=89.97-10.85 \\ 7y=79.12 \\ y=(79.12)/(7) \\ y\approx11.3 \end{gathered}`

Let's use the value of y to find the value of x

`x=2y=2\cdot11.3=22.6`

Therefore, each water ride costs $22.6.