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A normal force of 38 newtons acts on a book lying on a table. If the coefficient of static friction is 1.2, what is the minimum applied force required to slide the book?
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A normal force of 38 newtons acts on a book lying on a table. If the coefficient of static friction is 1.2, what is the minimum applied force required to slide the book?

User SmushyTaco
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7.1k points

2 Answers

4 votes

Answer:

B, 46 newtons for Plato users

Step-by-step explanation:

User Phk
by
6.8k points
3 votes
N = normal force = 38 newtons

Ks = coefficient of static friction = 1.2

Ff = maximum friction force = ks*N = 1.2 * 38 newtons = 45.6 newtons

F = minimum applied force = Ff

F = 45.6 newtons
User NessDan
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