Register
The length of a rectangle is 59 inches greater than twice the width. If the diagonal is 2 inches more than the​ length, find the dimensions of the rectangle.
11.1k views
0 votes
The length of a rectangle is 59 inches greater than twice the width. If the diagonal is 2 inches more than the​ length, find the dimensions of the rectangle.

User Daniel Schneller
by
7.6k points

2 Answers

7 votes

Answer:

The answer is 20

Explanation:

User Heathcliff
by
8.7k points
3 votes
d=2+20+2w=22+2w
so the eqations would be l=20+2w and d=22+2w
so when solving for the width, (20+2w)^2+w^2=(22+2w)^2
your equation would be : 400+80w+4w^2+w^2=484+44w+w^2
the anwer would be 1.9226

User Letfar
by
7.9k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.5m questions

12.2m answers

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
A bathtub is being filled with water. After 3 minutes 4/5 of the tub is full. Assuming the rate is constant, how much longer will it take to fill the tub?
i have a field 60m long and 110 wide going to be paved i ordered 660000000cm cubed of cement  how thick must the cement be to cover field
Write words to match the expression. 24- ( 6+3)
Link Copied!