The length of a rectangle is 59 inches greater than twice the width. If the diagonal is 2 inches more than the length, find the dimensions of the rectangle.

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asked Nov 9, 2017 11.1k views

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Letfar · Answer 1 · 2017-11-15T03:20:43+0000

d=2+20+2w=22+2w
so the eqations would be l=20+2w and d=22+2w
so when solving for the width, (20+2w)^2+w^2=(22+2w)^2
your equation would be : 400+80w+4w^2+w^2=484+44w+w^2
the anwer would be 1.9226

The length of a rectangle is 59 inches greater than twice the width. If the diagonal is 2 inches more than the length, find the dimensions of the rectangle.

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The length of a rectangle is 59 inches greater than twice the width. If the diagonal is 2 inches more than the​ length, find the dimensions of the rectangle.

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The length of a rectangle is 59 inches greater than twice the width. If the diagonal is 2 inches more than the length, find the dimensions of the rectangle.