Question

cindy exerts a force of 40 newtons and moves a chair 6 meters. her brother andy pushes a different chair for 6 meters while exerting a force of 30 newtons. andy does work than cindy. the difference of their amounts of work is nm.

Answer 1

The difference of their amounts of work is 60 Nm.

Step-by-step explanation:

Given that,

Force exerted by Cindy = 40 N

Distance = 6 m

Force exerted by her brother = 30 N

Distance = 6 m

We need to calculate the work done by Cindy

Using formula of work done

`W=F\cdot d`

Put the value into the formula

`W_(c)=40*6`

`W_(c)=240\ Nm`

We need to calculate the work done by her brother

Using formula of work done

`W=F\cdot d`

Put the value into the formula

`W_(b)=30*6`

`W_(b)=180\ Nm`

We need to calculate the difference of their amounts of work

The difference of work done is

`W=W_(c)-W_(b)`

Put the value into the formula

`W=240-180`

`W=60\ Nm`

Hence, The difference of their amounts of work is 60 Nm.

Answer 2

Work formula:
W = F * d
F 1 = 40 N, d 1 = 6 m;
F 2 = 30 N; d 2 = 6 m.
W ( Cindy ) = 40 * 6 = 240 Nm
W ( Andy ) = 30 * 6 = 180 Nm
The difference of their amounts if work:
240 Nm - 180 Nm = 60 Nm