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Given f(x)=x^2+2x+3 and g(x)=x+4/3 solve for f(g(x)) when x=2
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Given f(x)=x^2+2x+3 and g(x)=x+4/3 solve for f(g(x)) when x=2

User Ymyzk
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1 Answer

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f(x) = x^2 + 2x + 3
g(x) = (x + 4)/3
f(g(x)) = ((x + 4)/3)^2 + 2((x + 4)/3) + 3
f(g(2)) = ((2 + 4)/3)^2 + 2((2 + 4)/3) + 3 = (6/3)^2 + 2(6/3) + 3 = 2^2 + 2(2) + 3 = 4 + 4 + 3 = 11
User Deniz Ozger
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