Question

DeShawn and Bill are selling pies for a school fundraiser. Customers can buy apple pies and blackberry pies. DeShawn sold 3 apple pies and 7 blackberry pies for a total of $99. Bill sold 2 apple pies and 14 blackberry pies for a total of $178. What is the cost each of one apple pie and one blackberry pie

Answer 1

3 apple + 7 blackberrys = 99

2 apple + 14 blackberrys = 178

Then now find

apples = (99 - 7 B)/3 = (178 - 14B)/2

Now make cross multiply

(99 - 7B) •2 = (178 - 14B) •3

Solve parenthesis, use a (b+c) = ab + ac

Then

198 - 14B = 534 - 42B

Now find Blackberrys B PRICE

42B - 14B = 534 - 198

28B = 336

B= 336/28 = 12

Now find Apples price

Apples= ( 99 - 7B) /3 = (99 - 7•12)/3 = 15/3= 5

Then final answer is

Apple's price= $5

Blackberry's price= $12