Question

Blaine skis down a hill at an angle of 12°. He has a mass of 82 kg. What is the normal force on Blaine?

Answer 1

Normal force on an incline is
`N=m * g * cos(x)` Where
`m = 82kg` and
`g = 9.8 m/s2`

Therefore:


`N=82 * 9.8 * cos(12)`

`N=803.6 * cos(12)`

`N=803.6 * .98`

`N=787.528`

Normal force is 787.528 N.

Answer 2

The answer is . . . 786.8 N (see work attached)

normal force = (mg)cos(θ) = (82kg)(9.81 m/s²)cos(12⁰) = 786.8 N