Question

what is the solution to set to the inequality (4x-3)(2x-1)_>0 a) x<_3 or x_>1 b) x<_2 or x_> 4/3 c) x d) x<_-1/2 or x_>-3/4

Answer 1

(4x - 3)(2x - 1) ≥ 0
4x - 3 ≥ 0 or 2x - 1 ≤ 0
+ 3 + 3 + 1 + 1
4x ≥ 3 2x ≤ 1
4 4 2 2
x ≥ ³/₄ x ≤ ¹/₂
x ∈ [-∞, ¹/₂] ∧ [³/₄, ∞]

The answer is C.