Question

What is the 149th term in the arithmetic sequence below?

3 11 19 27

A) a(149) = 1187

B) a(149) = 1199

C) a) 149) = 1184

D) a(149) = 1189

I got 141 obviously that's completely incorrect plz help ​

Answer 1

1,187

Explanation:

The nth term of an arithmetic sequence is expressed as;

an = a + (n-1)d

a is the first term

n is the number of terms

d is the common difference

Given the sequence 3, 11, 19, 27...

a = 3

d = 11-3 = 19-11 = 8

n = 149 (since we need the 149th term)

a149 = 3 + (149-1)(8)

a149 = 3+(148)(8)

a149 = 3+1,184

a149 = 1,187

Hence the 149th term is 1,187