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What is the equation of the line that contains the two points (0 -1) and (-1 -3)

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Equation of a line is given by y - y1 = m(x - x1); where m = (y2 - y1)/(x2 - x1)

y - (-1) = ((-3 - (-1))/(-1 - 0))(x - 0)
y + 1 = ((-3 + 1)/-1)(x)
y + 1 = -2/-1(x)
y + 1 = 2x
y = 2x - 1

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