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What are four consecutive integers with the sum of 318

2 Answers

0 votes
The numbers are 20, 21, 22, and 23.
User Monnef
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3 votes
consecutive integers are 1 apart
they are
x,x+1,x+2,x+3

sum is 318

x+x+1+x+2+x+3=318
4x+6=318
minus 6 from both sides
4x=312
divide both sides by 4
x=78

x+1=79
x+2=80
x+3=81


they are
78,79,80,81
User BerndK
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