Question

Which of the following is not a way to represent the solution of the inequality 2(x + 1) greater than or equal to 20?

A) x __>__ 9
B) 9_<__ x
C) A number line with a closed circle on 9 and shading to the left.
D ) A number line with a closed circle on 9 and shading to the right.

Answer 1

`2x+2 \geq 20 2x \geq 18 x \geq 9 9 \leq x` which is the same with the one above

The answer to your question is C.A number line with a closed circle on 9 and shading to the left. I hope that this is the answer that you were looking for and it has helped you.

Answer 2

option C

A number line with a closed circle on
`9` and shading to the left

Explanation:

we have

`2(x+1)\geq 20`

solve for x

`2x+2\geq 20`

Subtract
`2` both sides

`2x+2-2\geq 20-2`

`2x\geq 18`

Divide by
`2` both sides

`x\geq 9` --------> is equivalent to
`9 \leq x`

The solution is the interval--------> [9,∞)

All real numbers greater than or equal to
`9`

A number line with a closed circle on
`9` and shading to the right