The base area of cube B is 25/9 times larger than the base area of cube A
How many times larger is the base area of cube B than the base area of cube A?
From the question, we have the following parameters that can be used in our computation:
Volume A = 27 cubic inches
Volume B = 125 cubic inches
Using the above as a guide, we have the following:
Side length A = 3 inches
Side length B = 5 inches
So, we have the areas to be
Area A = 3 inches * 3 inches = 9 square inches
Area B = 5 inches * 5 inches = 25 square inches
So, we have
The number of times, n is
n = 25/9
Hence, the base area of cube B is 25/9 times larger than the base area of cube A