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Graph the function
Need help ASAP plz

Graph the function Need help ASAP plz-example-1

1 Answer

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Given:

The equation of a function is


y=(x-4)^2+1

To find:

The graph of the given function.

Solution:

The vertex form of a parabola is


y=(x-h)^2+k ...(i)

Where, (h,k) is vertex of the parabola.

We have,


y=(x-4)^2+1 ...(ii)

From (i) and (ii), we get


h=4, k=1

The vertex of the parabola is (4,1).

Now, the table of values is

x y

2 5

3 2

4 1

5 2

6 5

Plot these points on a coordinate plane and connect them by a free hand curve.

The graph of given function is shown below.

Graph the function Need help ASAP plz-example-1
User Daquana
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