211k views
4 votes
Write an equation that is perpendicular to the line y = 5x - 1 and passes through the point (10, 8)

User Magellan
by
8.1k points

1 Answer

4 votes

Answer:

y = -1/5 x + 10

Explanation:

The equation of a line in point slope form is expressed as;

y - y0 = m(x-x0)

m is the slope

(x0, y0) is the point on the line

Given the equation y = 5x -1

Slope m = 5

Slope of the line perpendicular to the line will bw M = -1/5

Substitute into the equation

y - 8 = -1/5(x-10)

5(y-8) = -(x-10)

5y - 40 = -x+10

5y = -x+10+40

5y = -x+50

y = -1/5 x + 10

Hence the required equation is y = -1/5 x + 10

User Roqz
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories