Question

A ball rolls with a speed of 3 m/s across a level table that is 1.5m above the floor. How far along the floor is the landing spot from the table?

Answer 1

d = 1.65 m

Step-by-step explanation:

Given that,

The speed of a ball, v = 3 m/s

A ball rolls a level table that is 1.5 m above the floor.

We can find how long the ball is in free fall. We can use the second equation of kinematics as follows :

`s=ut+(1)/(2)gt^2`

u is the initial speed in the vertical direction

So,

`s=(1)/(2)gt^2\\\\t=\sqrt{(2s)/(g)} \\\\t=\sqrt{(2* 1.5)/(9.8)} \\\\t=0.55\ s`

Now, using the formula of velocity.

`v=(d)/(t)\\\\d=vt\\\\d=3* 0.55\\\\d=1.65\ m`

So, the landing spot is at 1.65 m from the table.